Find the area of the hexagon ABCDEF in which each side measures 17 cm, width BD=30 cm, and height CF=33 cm.
Answer:
750 cm2
- Let us join CF and draw AL⊥CF.
- Area of hexagon ABCDEF= Area of trapezium ABCF + Area of trapezium CDEF =2× Area of trapezium ABCF [Area of both the trapeziums will be same.]=2×12(AB+CF)×AL=(17+33)×15 cm2=750 cm2