What is the sum of the first n terms of the geometric series 1,35,925 ...?


Answer:

52[1(35)n]

Step by Step Explanation:
  1. The sum of first n terms of a G.P. is given by,
    Sn=a(1rn)(1r)
    Here, the first term, a=1 and
    the common ratio, r=ak+1ak where k1
    r=351=35
  2. The sum of first n terms of this G.P. is given by,
    Sn=(1)(1(35)n)135=(1(35)n)25=52[1(35)n]
  3. Hence, the sum of the first n terms of the G.P. is 52[1(35)n].

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